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      Software Developer Interview

      12 Jan 2021
      Anonymous interview candidate
      Los Angeles, CA
      Declined offer
      Positive experience
      Average interview

      Application

      I applied through a recruiter. I interviewed at Whisper (Los Angeles, CA) in Apr 2017

      Interview

      3 step interview. Started with a basic screening, asked about experience and engineering background. Then specialized questions and a coding example using some online toool (cant remember which one). The last one was more HR focused. Pretty straightforward process and very transparent.

      Interview questions [1]

      Question 1

      Multiple string manipulation examples and problems.
      Answer question

      Other Software Developer interview reviews for Whisper

      Software Developer Interview

      3 Oct 2018
      Anonymous employee
      Venice, CA
      Accepted offer
      Positive experience
      Difficult interview

      Application

      I applied through an employee referral. The process took 1 week. I interviewed at Whisper (Venice, CA) in Jun 2017

      Interview

      I had a phone screen with someone, and then I flew out the next week for several in person interviews. I also had lunch at the office with several employees and then heard back from them the next day.

      Interview questions [1]

      Question 1

      Why I wanted to work for whisper
      1 Answer

      Software Engineer Interview

      7 Jan 2016
      Anonymous interview candidate
      No offer
      Neutral experience
      Difficult interview

      Application

      I applied online. The process took 2 days. I interviewed at Whisper in Jan 2016

      Interview

      I applied online and a recruiter reached out to me to schedule phone screen with an engineer. I didn't continue in the process because I didn't pass the inital phone screen.

      Interview questions [1]

      Question 1

      1. Calculate how many times 10 can by divisible by a number? - Gave an O(n) Solution: public int count(int n){ if(n == 0){ return 1; } int count = 0; while(n % 10 == 0){ count++; n /= 10; } return count; } 2. How can you do better than linear? - Was a lot more difficult for me, but finally got an O(log n) Solution public int binarySearch(int val, int start, int end){ if(start > end){ return -1; } int mid = (start + end) / 2; if(val % 10^(length - i) == 0 && ((val / 10^(length - i)) % 10) != 0){ return (length - i); } else{ // if value is non 0, search right for value // if value is 0, search left for value if(val % 10^(length - i) != 0){ binarySearch(val, mid+1, end); else{ binarySearch(val,start, mid-1); } } } 3. Given 2 people, find if one is the ancestor of another? These are actual people so, there is a mother and father who are ancestors of their son, along with grandmothers and grandfathers. (Not a tree) Given: def isAncestor(me, anotherPerson): class Person: string id string name int gender date dob - What if the path up the tree is very long? It takes a long time to traverse up? - Can store additional info in the Person class
      1 Answer

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