Yes, the sequence:
√11, √55, 5√11, 5√55, 25√11
is an arithmetic progression (AP) with a common difference.
To confirm:
1. √55 - √11 = 4√11 (difference between 1st and 2nd terms)
2. 5√11 - √55 = 4√11 (difference between 2nd and 3rd terms)
3. 5√55 - 5√11 = 4√11 (difference between 3rd and 4th terms)
4. 25√11 - 5√55 = 4√11 (difference between 4th and 5th terms)
The common difference (d) is:
d = 4√11
The sequence follows the AP formula:
an = a1 + (n-1)d
where:
a1 = √11 (first term)
d = 4√11 (common difference)
n = term number
Well done!
Would you like to explore more properties or find the nth term?
