What will be the output produced by the following C code:
int main()
{
int array[5][5];
printf("%d",( (array == *array) && (*array == array[0]) ));
return 0;
}

Question

What will be the output produced by the following C code:
int main()
{
    int array[5][5];
    printf("%d",( (array == *array) && (*array == array[0]) ));
    return 0;    
}

Anonymous · Accepted Answer

array is a 2D array → type is int[5][5]
array means → first row of the array → so, it's int[5]
array == *array → both point to the same starting address of row 0 → so true

*array == array[0] → both also point to the 1D array of first row → again true

So, both conditions are true → true && true = 1

That's why output is 1

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