One pattern Question
one was printing no from 1 to n without using loops.

Question

One pattern Question
one was printing no from 1 to n without using loops.

Mainong · Accepted Answer

import java.util.Scanner;

public class CountDemo {

  static int count = 1;
  public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter the value for N");
    int n = scan.nextInt();
    scan.close();
    display(n);
  }

  static void display(int n) {
    if (count <= n) {
      System.out.println("" + count);
      count++;
      display(n);
    }

  }
}

print 1 to n without using loops,lets take n=100 · Answer

public static void main(String[] args) 
    {		printNumber(1);
	}
 
	public static void printNumber(int number) {
		if(number <= 100) {
			System.out.println(number);
			number++;
			printNumber(number);			//Note: method calling itself
		}else {
			System.exit(0);
		}
	}

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